możesz użyć case
w tym przypadku -
SELECT type,
sum(case when place = 'home' then 1 else 0 end) as Home,
sum(case when place = 'school' then 1 else 0 end) as school,
sum(case when place = 'work' then 1 else 0 end) as work,
sum(case when place = 'cafe' then 1 else 0 end) as cafe,
sum(case when place = 'friends' then 1 else 0 end) as friends,
sum(case when place = 'mall' then 1 else 0 end) as mall
from reports
group by type
To powinno rozwiązać Twój problem
@S T Mohammed,Aby uzyskać taki typ, wystarczy użyć using
po group
lub where
warunek w zewnętrznym zapytaniu, jak poniżej -
select type, Home, school, work, cafe, friends, mall from (
SELECT type,
sum(case when place = 'home' then 1 else 0 end) as Home,
sum(case when place = 'school' then 1 else 0 end) as school,
sum(case when place = 'work' then 1 else 0 end) as work,
sum(case when place = 'cafe' then 1 else 0 end) as cafe,
sum(case when place = 'friends' then 1 else 0 end) as friends,
sum(case when place = 'mall' then 1 else 0 end) as mall
from reports
group by type
)
where home >0 and School >0 and Work >0 and cafe>0 and friends>0 and mall>0