To jest uproszczona wersja poprawny @a_horse odpowiedz
(po dyskusji z OP w komentarzach).
Działa z każdym (rozsądnie skończona) liczba poziomów w rekurencji.
Całkowita cena za podany project_id
WITH RECURSIVE cte AS (
SELECT project_id AS project_parent, project_value
FROM projects
WHERE project_id = 1 -- enter id of the base project here !
UNION ALL
SELECT p.project_id, p.project_value
FROM cte
JOIN projects p USING (project_parent)
)
SELECT sum(project_value) AS total_value
FROM cte;
Cena łączna za wszystkie projekty
WITH RECURSIVE cte AS (
SELECT project_id, project_id AS project_parent, project_value
FROM projects
WHERE project_parent IS NULL -- all base projects
UNION ALL
SELECT c.project_id, p.project_id, p.project_value
FROM cte c
JOIN projects p USING (project_parent)
)
SELECT project_id, sum(project_value) AS total_value
FROM cte
GROUP BY 1
ORDER BY 1;
db<>fiddle tutaj
(z poprawnym przypadkiem testowym)
Stary sqlfiddle