SQL Query - zbieraj dane na podstawie zakresu dat - możliwa zmienna liczba kolumn

To było interesujące. Myślę, że to zrobi to, czego szukasz. Pierwsze dane testowe:

CREATE TABLE people (PersonID int, Name varchar(30))

INSERT INTO people (PersonID, Name)
SELECT 1, 'Kelly'
UNION ALL SELECT 2, 'Dave'
UNION ALL SELECT 3, 'Mike'

CREATE TABLE attendances (PersonID int, SignIn datetime, SignOut datetime)

INSERT INTO attendances (PersonID, SignIn, SignOut)
SELECT 1, '1-Feb-2015 08:00', '1-Feb-2015 09:00'
UNION ALL SELECT 1, '1-Feb-2015 12:00', '1-Feb-2015 12:30'
UNION ALL SELECT 2, '2-Feb-2015 08:00', '2-Feb-2015 08:15'
UNION ALL SELECT 1, '3-Feb-2015 08:00', '3-Feb-2015 09:00'
UNION ALL SELECT 1, '4-Feb-2015 08:00', '4-Feb-2015 08:30'
UNION ALL SELECT 2, '4-Feb-2015 08:00', '4-Feb-2015 10:00'
UNION ALL SELECT 2, '6-Feb-2015 12:00', '6-Feb-2015 15:00'
UNION ALL SELECT 3, '6-Feb-2015 15:00', '6-Feb-2015 17:00'
UNION ALL SELECT 3, '8-Feb-2015 10:00', '8-Feb-2015 12:00'

Następnie dynamiczne zapytanie:

DECLARE @startDate DATETIME='1-Feb-2015'
DECLARE @endDate DATETIME='9-Feb-2015'
DECLARE @numberOfDays INT = DATEDIFF(DAY, @startDate, @endDate)

declare @dayColumns TABLE (delta int, colName varchar(12))

-- Produce 1 row for each day in the report. Note that this is limited by the 
-- number of objects in sysobjects (which is about 2000 so it's a high limit)
-- Each row contains a delta date offset, @startDate+delta gives each date to report 
-- which is converted to a valid SQL column name in the format colYYYYMMDD
INSERT INTO @dayColumns (delta, colName)
SELECT delta, 'col'+CONVERT(varchar(12),DATEADD(day,delta,@startDate),112) as colName from (
  select (ROW_NUMBER() OVER (ORDER BY sysobjects.id))-1 as delta FROM sysobjects 
) daysAhead
WHERE delta<[email protected]

-- Create a comma seperated list of columns to report
DECLARE @cols AS NVARCHAR(MAX)= ''
SELECT @cols=CASE WHEN @cols='' THEN @cols ELSE @cols+',' END + colName FROM @dayColumns ORDER BY delta
DECLARE @totalHours AS NVARCHAR(MAX)= ''
SELECT @totalHours=CASE WHEN @totalHours='' THEN '' ELSE @totalHours+' + ' END + 'ISNULL(' + colName +',0)' FROM @dayColumns ORDER BY delta

-- Produce a SQL statement which outputs a variable number of pivoted columns
DECLARE @query AS NVARCHAR(MAX)
SELECT @query=
'declare @days TABLE (reportDay date, colName varchar(12))

INSERT INTO @days (reportDay, colName)
SELECT DATEADD(day,Delta,'''+CONVERT(varchar(22),@startDate,121)+'''), ''col''+CONVERT(varchar(12),DATEADD(day,delta,'''+CONVERT(varchar(22),@startDate,121)+'''),112) as colName from (
  select (ROW_NUMBER() OVER (ORDER BY sysobjects.id))-1 as Delta FROM sysobjects 
) daysAhead
WHERE Delta<='+CAST(@numberOfDays as varchar(10))+'

SELECT p.Name, pivotedAttendance.*,'[email protected]+' as totalHours FROM (
  SELECT * FROM (
    select p.PersonID, d.colName, CAST(DATEDIFF(MINUTE, a.SignIn, a.SignOut)/60.0 as decimal(5,1)) as hrsAttendance 
    from @days d
    CROSS JOIN people p 
    LEFT OUTER JOIN attendances a ON a.PersonID=p.PersonID AND CAST(a.SignOut as DATE)=d.reportDay
  ) as s
  PIVOT (
    SUM(hrsAttendance) FOR colName in ('[email protected]+')
  ) as pa
) as pivotedAttendance
INNER JOIN people p on p.PersonID=pivotedAttendance.PersonID'

-- Run the query
EXEC (@query)

Daje to dane w formacie podobnym do twojego przykładu, ze wszystkimi dniami w zakresie raportu i wierszem dla każdej osoby. Z powyższego widzę:

Do celów prezentacji powinieneś być w stanie przekonwertować nazwę kolumny na datę możliwą do wyświetlenia (wystarczy przeanalizować RRRRMMDD z nazwy kolumny). Data nie może być użyta jako nazwa kolumny bezpośrednio, ponieważ powoduje to nieprawidłową nazwę kolumny.

Przykład SQL Fiddle tutaj .