Chociaż nigdzie nie ma dokumentacji dotyczącej mojej odpowiedzi, po dokładnych eksperymentach doszedłem do tego najbardziej logicznego wniosku -
Obecność operatora „+” unieważnia każdy efekt operatora „~”
Zaktualizowałem moją tabelę fruits z następującymi wartościami -
SELECT * FROM fruits;
+----+-------------------------+
| id | name |
+----+-------------------------+
| 1 | apple orange watermelon |
| 2 | apple mango pomegranate |
| 3 | apple mango banana |
| 4 | mango kiwi pomegranate |
| 5 | mango guava watermelon |
| 6 | apple banana kiwi |
+----+-------------------------+
Zapytanie 1:
SELECT id, name FROM fruits
-> WHERE MATCH(name) AGAINST
-> ('apple mango ~pomegranate'
-> IN BOOLEAN MODE);
+----+-------------------------+
| id | name |
+----+-------------------------+
| 3 | apple mango banana |
| 1 | apple orange watermelon |
| 5 | mango guava watermelon |
| 6 | apple banana kiwi |
| 2 | apple mango pomegranate |
| 4 | mango kiwi pomegranate |
+----+-------------------------+
Zapytanie 2:
SELECT id, name FROM fruits
-> WHERE MATCH(name) AGAINST
-> ('apple ~pomegranate'
-> IN BOOLEAN MODE);
+----+-------------------------+
| id | name |
+----+-------------------------+
| 1 | apple orange watermelon |
| 3 | apple mango banana |
| 6 | apple banana kiwi |
| 2 | apple mango pomegranate |
+----+-------------------------+
Zapytanie 3:
SELECT id, name FROM fruits
-> WHERE MATCH(name) AGAINST
-> ('mango ~pomegranate'
-> IN BOOLEAN MODE);
+----+-------------------------+
| id | name |
+----+-------------------------+
| 3 | apple mango banana |
| 5 | mango guava watermelon |
| 2 | apple mango pomegranate |
| 4 | mango kiwi pomegranate |
+----+-------------------------+
Tutaj w zapytaniach 1, 2 i 3 żaden operator nie poprzedza wartości apple i mango i ~ operator poprzedza wartość pomegranate . Dzięki temu wiersze zawierające słowo pomegranate zajmują niższą pozycję w rankingu niż inne.
Zapytanie 4:
SELECT id, name FROM fruits
-> WHERE MATCH(name) AGAINST
-> ('+apple +mango ~pomegranate'
-> IN BOOLEAN MODE);
+----+-------------------------+
| id | name |
+----+-------------------------+
| 2 | apple mango pomegranate |
| 3 | apple mango banana |
+----+-------------------------+
Zapytanie 5:
SELECT id, name FROM fruits
-> WHERE MATCH(name) AGAINST
-> ('+apple ~pomegranate'
-> IN BOOLEAN MODE);
+----+-------------------------+
| id | name |
+----+-------------------------+
| 1 | apple orange watermelon |
| 2 | apple mango pomegranate |
| 3 | apple mango banana |
| 6 | apple banana kiwi |
+----+-------------------------+
Pytanie 6:
SELECT id, name FROM fruits
-> WHERE MATCH(name) AGAINST
-> ('+mango ~pomegranate'
-> IN BOOLEAN MODE);
+----+-------------------------+
| id | name |
+----+-------------------------+
| 2 | apple mango pomegranate |
| 3 | apple mango banana |
| 4 | mango kiwi pomegranate |
| 5 | mango guava watermelon |
+----+-------------------------+
Tutaj, w zapytaniach 4, 5 i 6 + operator poprzedza wartości apple i mango i ~ operator poprzedza wartość pomegranate . Wyraźnie obecność + operator unieważnia każdy efekt ~ operatora.
Zapytanie 7:
SELECT id, name FROM fruits
-> WHERE MATCH(name) AGAINST
-> ('+apple +mango <pomegranate'
-> IN BOOLEAN MODE);
+----+-------------------------+
| id | name |
+----+-------------------------+
| 3 | apple mango banana |
| 2 | apple mango pomegranate |
+----+-------------------------+
Zapytanie 8:
SELECT id, name FROM fruits
-> WHERE MATCH(name) AGAINST
-> ('+apple <pomegranate'
-> IN BOOLEAN MODE);
+----+-------------------------+
| id | name |
+----+-------------------------+
| 1 | apple orange watermelon |
| 3 | apple mango banana |
| 6 | apple banana kiwi |
| 2 | apple mango pomegranate |
+----+-------------------------+
Pytanie 9:
SELECT id, name FROM fruits
-> WHERE MATCH(name) AGAINST
-> ('+mango <pomegranate'
-> IN BOOLEAN MODE);
+----+-------------------------+
| id | name |
+----+-------------------------+
| 3 | apple mango banana |
| 5 | mango guava watermelon |
| 2 | apple mango pomegranate |
| 4 | mango kiwi pomegranate |
+----+-------------------------+
Tutaj, w zapytaniach 7, 8 i 9 + operator poprzedza wartości apple i mango i < operator poprzedza wartość pomegranate . Dzięki temu wiersze zawierające słowo pomegranate zajmują niższą pozycję w rankingu niż inne.
Stąd można wywnioskować, że -if + operator jest obecny, użyj < operator zamiast ~ operator
AKTUALIZUJ
Po rozbudowanych obliczeniach stworzyłem tabelę fruits_score_count który pokazuje score każdego fruit po zakończeniu wyszukiwania logicznego FULLTEXT.
SELECT * FROM fruits_score_count;
+----+-------------+---------------------+----------------------+
| id | fruit_name | row_numbers_matched | score |
+----+-------------+---------------------+----------------------+
| 1 | apple | 4 | 0.031008131802082062 |
| 2 | banana | 2 | 0.22764469683170319 |
| 3 | guava | 1 | 0.6055193543434143 |
| 4 | kiwi | 2 | 0.22764469683170319 |
| 5 | mango | 4 | 0.031008131802082062 |
| 6 | orange | 1 | 0.6055193543434143 |
| 7 | pomegranate | 2 | 0.22764469683170319 |
| 8 | watermelon | 2 | 0.22764469683170319 |
+----+-------------+---------------------+----------------------+
Zapytanie 1:
SELECT id, name, score FROM
-> (SELECT id, name, MATCH(name) AGAINST
-> ('apple mango ~pomegranate' IN BOOLEAN MODE)
-> AS score FROM fruits ORDER BY score DESC)
-> AS temp WHERE score != 0;
+----+-------------------------+----------------------+
| id | name | score |
+----+-------------------------+----------------------+
| 3 | apple mango banana | 0.062016263604164124 |
| 1 | apple orange watermelon | 0.031008131802082062 |
| 5 | mango guava watermelon | 0.031008131802082062 |
| 6 | apple banana kiwi | 0.031008131802082062 |
| 2 | apple mango pomegranate | -0.7103390693664551 |
| 4 | mango kiwi pomegranate | -0.7413471937179565 |
+----+-------------------------+----------------------+
Zapytanie 2:
SELECT id, name, score FROM
-> (SELECT id, name, MATCH(name) AGAINST
-> ('apple ~pomegranate' IN BOOLEAN MODE)
-> AS score FROM fruits ORDER BY score DESC)
-> AS temp WHERE score != 0;
+----+-------------------------+----------------------+
| id | name | score |
+----+-------------------------+----------------------+
| 1 | apple orange watermelon | 0.031008131802082062 |
| 3 | apple mango banana | 0.031008131802082062 |
| 6 | apple banana kiwi | 0.031008131802082062 |
| 2 | apple mango pomegranate | -0.7413471937179565 |
+----+-------------------------+----------------------+
Zapytanie 3:
SELECT id, name, score FROM
-> (SELECT id, name, MATCH(name) AGAINST
-> ('mango ~pomegranate' IN BOOLEAN MODE)
-> AS score FROM fruits ORDER BY score DESC)
-> AS temp WHERE score != 0;
+----+-------------------------+----------------------+
| id | name | score |
+----+-------------------------+----------------------+
| 3 | apple mango banana | 0.031008131802082062 |
| 5 | mango guava watermelon | 0.031008131802082062 |
| 2 | apple mango pomegranate | -0.7413471937179565 |
| 4 | mango kiwi pomegranate | -0.7413471937179565 |
+----+-------------------------+----------------------+
Zapytanie 4:
SELECT id, name, score FROM
-> (SELECT id, name, MATCH(name) AGAINST
-> ('+apple +mango ~pomegranate' IN BOOLEAN MODE)
-> AS score FROM fruits ORDER BY score DESC)
-> AS temp WHERE score != 0;
+----+-------------------------+----------------------+
| id | name | score |
+----+-------------------------+----------------------+
| 2 | apple mango pomegranate | 0.062016263604164124 |
| 3 | apple mango banana | 0.062016263604164124 |
+----+-------------------------+----------------------+
Zapytanie 5:
SELECT id, name, score FROM
-> (SELECT id, name, MATCH(name) AGAINST
-> ('+apple ~pomegranate' IN BOOLEAN MODE)
-> AS score FROM fruits ORDER BY score DESC)
-> AS temp WHERE score != 0;
+----+-------------------------+----------------------+
| id | name | score |
+----+-------------------------+----------------------+
| 1 | apple orange watermelon | 0.031008131802082062 |
| 2 | apple mango pomegranate | 0.031008131802082062 |
| 3 | apple mango banana | 0.031008131802082062 |
| 6 | apple banana kiwi | 0.031008131802082062 |
+----+-------------------------+----------------------+
Pytanie 6:
SELECT id, name, score FROM
-> (SELECT id, name, MATCH(name) AGAINST
-> ('+mango ~pomegranate' IN BOOLEAN MODE)
-> AS score FROM fruits ORDER BY score DESC)
-> AS temp WHERE score != 0;
+----+-------------------------+----------------------+
| id | name | score |
+----+-------------------------+----------------------+
| 2 | apple mango pomegranate | 0.031008131802082062 |
| 3 | apple mango banana | 0.031008131802082062 |
| 4 | mango kiwi pomegranate | 0.031008131802082062 |
| 5 | mango guava watermelon | 0.031008131802082062 |
+----+-------------------------+----------------------+
Zapytanie 7:
SELECT id, name, score FROM
-> (SELECT id, name, MATCH(name) AGAINST
-> ('+apple +mango <pomegranate' IN BOOLEAN MODE)
-> AS score FROM fruits ORDER BY score DESC)
-> AS temp WHERE score != 0;
+----+-------------------------+----------------------+
| id | name | score |
+----+-------------------------+----------------------+
| 3 | apple mango banana | 0.062016263604164124 |
| 2 | apple mango pomegranate | -0.7103390693664551 |
+----+-------------------------+----------------------+
Zapytanie 8:
SELECT id, name, score FROM
-> (SELECT id, name, MATCH(name) AGAINST
-> ('+apple <pomegranate' IN BOOLEAN MODE)
-> AS score FROM fruits ORDER BY score DESC)
-> AS temp WHERE score != 0;
+----+-------------------------+----------------------+
| id | name | score |
+----+-------------------------+----------------------+
| 1 | apple orange watermelon | 0.031008131802082062 |
| 3 | apple mango banana | 0.031008131802082062 |
| 6 | apple banana kiwi | 0.031008131802082062 |
| 2 | apple mango pomegranate | -0.7413471937179565 |
+----+-------------------------+----------------------+
Pytanie 9:
SELECT id, name, score FROM
-> (SELECT id, name, MATCH(name) AGAINST
-> ('+mango <pomegranate' IN BOOLEAN MODE)
-> AS score FROM fruits ORDER BY score DESC)
-> AS temp WHERE score != 0;
+----+-------------------------+----------------------+
| id | name | score |
+----+-------------------------+----------------------+
| 3 | apple mango banana | 0.031008131802082062 |
| 5 | mango guava watermelon | 0.031008131802082062 |
| 2 | apple mango pomegranate | -0.7413471937179565 |
| 4 | mango kiwi pomegranate | -0.7413471937179565 |
+----+-------------------------+----------------------+
Tutaj Zapytanie 1, Zapytanie 2, Zapytanie 3, Zapytanie 7, Zapytanie 8, Zapytanie 9 zachowują się zgodnie z oczekiwaniami.
Ale z Zapytania 4, Zapytania 5, Zapytania 6 jasne jest, że -
W obecności + operator poprzedzający wartość ~ operator zasadniczo sprawia, że wartość jest niewidoczna.
Również uważna obserwacja ujawnia, że -
x ~y i +x <y są równoważne
DALSZE EKSPERYMENTY
Zapytanie 1:
SELECT id, name, score FROM
-> (SELECT id, name, MATCH(name) AGAINST
-> ('+mango apple ~pomegranate' IN BOOLEAN MODE)
-> AS score FROM fruits ORDER BY score DESC)
-> AS temp WHERE score != 0;
+----+-------------------------+----------------------+
| id | name | score |
+----+-------------------------+----------------------+
| 3 | apple mango banana | 0.062016263604164124 |
| 4 | mango kiwi pomegranate | 0.031008131802082062 |
| 5 | mango guava watermelon | 0.031008131802082062 |
| 2 | apple mango pomegranate | -0.7103390693664551 |
+----+-------------------------+----------------------+
- Wiersz 1 z
id = 3otrzymuje maksymalny wynik, który jest sumą wynikówmangoiapple. - Wiersz 2 z
id = 4otrzymuje drugi maksymalny wynik, który jest wynikiemmango. Obecność+operator przedmangosprawia, że ~pomegranatewyszukiwanej frazy nietrafnej. - Wiersz 3 z
id = 5otrzymuje taki sam wynik jak w wierszu 2. Ale jest umieszczony niżej niż w wierszu 2, ponieważ gdy wyniki są takie same, wiersze są uszeregowane w kolejności rosnącej odprimary key, tutajidtoprimary key. - Wiersz 4 z
id = 2otrzymuje najniższy wynik i dlatego jest ostatni. Tutaj od słowaapplejest obecny i w wyszukiwanej frazie nie ma+operator poprzedzającyapple, stąd~pomegranatew wyszukiwanej frazie jest brana pod uwagę, co znacznie obniża wynik.
Zapytanie 2:
SELECT id, name, score FROM
-> (SELECT id, name, MATCH(name) AGAINST
-> ('+mango apple <pomegranate' IN BOOLEAN MODE)
-> AS score FROM fruits ORDER BY score DESC)
-> AS temp WHERE score != 0;
+----+-------------------------+----------------------+
| id | name | score |
+----+-------------------------+----------------------+
| 3 | apple mango banana | 0.062016263604164124 |
| 5 | mango guava watermelon | 0.031008131802082062 |
| 2 | apple mango pomegranate | -0.7103390693664551 |
| 4 | mango kiwi pomegranate | -0.7413471937179565 |
+----+-------------------------+----------------------+
To ponownie ilustruje, że < operator działa nawet w obecności + operatora.
To dodatkowo wzmacnia moją wcześniejszą obserwację, że -
jeśli + operator jest obecny, użyj < operator zamiast ~ operator