spróbuj z poniższym zapytaniem
Select * from employee a where Employee_Salary > (select avg(Employee_Salary) from
employee b group by Department_ID having b.Department_ID = a.Department_ID)
lub
Select * from employee a where Employee_Salary> (select avg(Employee_Salary) from
employee b where b.Department_ID = a.Department_ID group by Department_ID)