Pomoc w obliczaniu złożonej sumy w hierarchicznym zbiorze danych

W Oracle 11 R2 jest to możliwe za pomocą common table expression :

Dane testowe:

--  drop table assembly;

create table assembly (
  part_id              number, 
  parent_part_id       number,
  quantity             number
);

insert into assembly values (2, 1,  2);
insert into assembly values (3, 2, 10);
insert into assembly values (4, 1,  2);
insert into assembly values (5, 4,  1);
insert into assembly values (3, 5,  5);

Instrukcja select:

select 
  part_id, 
  sum(quantity_used) as quantity
from (
  with assembly_hier (lvl, part_id, quantity, quantity_used) as (
    select 
      1        lvl,
      part_id,
      quantity ,
      quantity        quantity_used
    from
      assembly
    where
      parent_part_id = 1 
  union all
    select
      assembly_hier.lvl      + 1 lvl,
      assembly     .part_id,
      assembly     .quantity,
      assembly_hier.quantity_used * assembly.quantity quantity_used
    from
      assembly_hier, assembly
    where
      assembly_hier.part_id = assembly.parent_part_id
  )
  select * from assembly_hier
)
group by part_id
order by part_id;

Edytuj Przed Ora11R2 może działać z model clause :

select 
  part_id,
  sum(quantity) quantity 
from (
  select
    lvl
    parent_part_id,
    part_id,
    quantity
  from (
    select 
      lvl,
      parent_part_id,
      part_id,
      quantity
    from (
      select  
        rownum r, 
        level lvl, 
        parent_part_id,
        part_id, 
        quantity
      from 
        assembly
      start with parent_part_id = 1
      connect by parent_part_id = prior part_id
    )
  )
  model
    dimension by (lvl, part_id)
    measures (quantity, parent_part_id)
    rules upsert (
       quantity[     any, any          ] order by lvl, part_id =   quantity[cv(lvl)  , cv(part_id)] * 
                                          nvl( quantity[cv(lvl)-1,    parent_part_id[cv(lvl), cv(part_id)] ], 1)
    )
)
group by part_id
order by part_id;

Edytuj II Inną możliwością byłoby zsumowanie logarytmów ilości, a następnie wzięcie wykładnika sumy:

select 
  part_id,
  sum(quantity) quantity
from (
  select 
    part_id,
    exp(sum(quantity_ln) over (partition by new_start order by r)) quantity
  from (
    select 
      r,
      lvl,
      part_id,
      quantity_ln,
      sum(new_start) over(order by r) new_start
    from (
      select 
        rownum r, 
        level lvl, 
        part_id, 
        ln(quantity) quantity_ln,
        nvl(lag(connect_by_isleaf,1) over (order by rownum),0) new_start
      from assembly
      start with parent_part_id = 1
      connect by parent_part_id = prior part_id
    )
  )
)
group by part_id
order by part_id
;