Oto funkcja, którą możesz utworzyć, aby się tym zająć
SQL> create or replace
2 function spell_number( p_number in number )
3 return varchar2
4 as
5 type myArray is table of varchar2(255);
6 l_str myArray := myArray( '',
7 ' thousand ', ' million ',
8 ' billion ', ' trillion ',
9 ' quadrillion ', ' quintillion ',
10 ' sextillion ', ' septillion ',
11 ' octillion ', ' nonillion ',
12 ' decillion ', ' undecillion ',
13 ' duodecillion ' );
14
15 l_num varchar2(50) default trunc( p_number );
16 l_return varchar2(4000);
17 begin
18 for i in 1 .. l_str.count
19 loop
20 exit when l_num is null;
21
22 if ( substr(l_num, length(l_num)-2, 3) <> 0 )
23 then
24 l_return := to_char(
25 to_date(
26 substr(l_num, length(l_num)-2, 3),
27 'J' ),
28 'Jsp' ) || l_str(i) || l_return;
29 end if;
30 l_num := substr( l_num, 1, length(l_num)-3 );
31 end loop;
32
33 return l_return;
34 end;
35 /
Function created.
SQL> select
2 spell_number( 12345678901234567890123456789012345678 )
3 from dual;
SPELL_NUMBER(1234567890123456789012345678901234567
--------------------------------------------------
Twelve undecillion Three Hundred Forty-Five decill
ion Six Hundred Seventy-Eight nonillion Nine Hundr
ed One octillion Two Hundred Thirty-Four septillio
n Five Hundred Sixty-Seven sextillion Eight Hundre
d Ninety quintillion One Hundred Twenty-Three quad
rillion Four Hundred Fifty-Six trillion Seven Hund
red Eighty-Nine billion Twelve million Three Hundr
ed Forty-Five thousand Six Hundred Seventy-Eight
