Zapytanie Pivot SQL — Pokaż datę w kolumnie

Aktualizacja 4 Ok, teraz, gdy umieściłeś już wszystkie swoje zapytania i podążając za komentarzami, powinieneś spróbować tego:

DECLARE @FirstDay SMALLDATETIME
SELECT @FirstDay = CONVERT(SMALLDATETIME, (@year + '-' + @month + '-01')); 

WITH Dates AS  
(
  SELECT @FirstDay AS DateVal 
  UNION ALL 
  SELECT DATEADD(d, 1, DateVal) AS DateVal 
  FROM Dates 
  WHERE DATEADD(d, 1, DateVal) < DATEADD(m, 1, @FirstDay)
)

SELECT * INTO #Dates FROM Dates

DECLARE @hotelID INT, @packageID INT, @year VARCHAR(4), @Dates VARCHAR(1000), @month VARCHAR(2), @Query VARCHAR(MAX)
SELECT @hotelID=248, @packageID=76, @year='2010', @month='12',@Dates=''

SELECT co.*,wb.Name,rc.HotelName 
INTO #HotelData
FROM RCompetitorOccupancy co 
INNER JOIN websites wb ON wb.websiteid=co.websiteid
INNER JOIN RoomCompetitor rc ON rc.competitorid=co.competitorid
WHERE YEAR(occDate)[email protected] AND MONTH(occdate)[email protected] AND [email protected] 
AND roomTypeid IN (SELECT roomtypeid FROM CompetitorRoomType WHERE DESCRIPTION=119)

SELECT @Dates = @Dates + '[' + CAST(DATEPART(DAY,DateVal) AS VARCHAR(2)) + '-' + LEFT(DATENAME(MONTH,DateVal),3)+ '],'
FROM #Dates
GROUP BY Dateval

SET @Dates = LEFT(@Dates,LEN(@Dates)-1)

SET @Query = '
SELECT roomtypeid, description, [Name], [HotelName], '[email protected]+'
FROM (  SELECT  HD.roomtypeid, HD.description, HD.[Name], HD.[HotelName], HD.Price, 
                CAST(DATEPART(DAY,DateVal) AS VARCHAR(2)) + ''-'' + LEFT(DATENAME(MONTH,DateVal),3) [Date]
        FROM #Dates D
        LEFT JOIN #HotelData HD
        ON D.DateVal = HD.OccDate) T
PIVOT ( SUM(Price) FOR [Date] IN ('[email protected]+') ) AS PT'

EXEC(@Query)